Optimal. Leaf size=516 \[ -\frac {(e+f x)^2}{2 b f}-\frac {2 a (e+f x) \text {ArcTan}\left (e^{c+d x}\right )}{b^2 d}+\frac {2 a^3 (e+f x) \text {ArcTan}\left (e^{c+d x}\right )}{b^2 \left (a^2+b^2\right ) d}+\frac {a^2 (e+f x) \log \left (1+\frac {b e^{c+d x}}{a-\sqrt {a^2+b^2}}\right )}{b \left (a^2+b^2\right ) d}+\frac {a^2 (e+f x) \log \left (1+\frac {b e^{c+d x}}{a+\sqrt {a^2+b^2}}\right )}{b \left (a^2+b^2\right ) d}+\frac {(e+f x) \log \left (1+e^{2 (c+d x)}\right )}{b d}-\frac {a^2 (e+f x) \log \left (1+e^{2 (c+d x)}\right )}{b \left (a^2+b^2\right ) d}+\frac {i a f \text {PolyLog}\left (2,-i e^{c+d x}\right )}{b^2 d^2}-\frac {i a^3 f \text {PolyLog}\left (2,-i e^{c+d x}\right )}{b^2 \left (a^2+b^2\right ) d^2}-\frac {i a f \text {PolyLog}\left (2,i e^{c+d x}\right )}{b^2 d^2}+\frac {i a^3 f \text {PolyLog}\left (2,i e^{c+d x}\right )}{b^2 \left (a^2+b^2\right ) d^2}+\frac {a^2 f \text {PolyLog}\left (2,-\frac {b e^{c+d x}}{a-\sqrt {a^2+b^2}}\right )}{b \left (a^2+b^2\right ) d^2}+\frac {a^2 f \text {PolyLog}\left (2,-\frac {b e^{c+d x}}{a+\sqrt {a^2+b^2}}\right )}{b \left (a^2+b^2\right ) d^2}+\frac {f \text {PolyLog}\left (2,-e^{2 (c+d x)}\right )}{2 b d^2}-\frac {a^2 f \text {PolyLog}\left (2,-e^{2 (c+d x)}\right )}{2 b \left (a^2+b^2\right ) d^2} \]
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Rubi [A]
time = 0.56, antiderivative size = 516, normalized size of antiderivative = 1.00, number of steps
used = 30, number of rules used = 10, integrand size = 30, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.333, Rules used = {5700, 3799,
2221, 2317, 2438, 5686, 4265, 5692, 5680, 6874} \begin {gather*} \frac {a^2 f \text {Li}_2\left (-\frac {b e^{c+d x}}{a-\sqrt {a^2+b^2}}\right )}{b d^2 \left (a^2+b^2\right )}+\frac {a^2 f \text {Li}_2\left (-\frac {b e^{c+d x}}{a+\sqrt {a^2+b^2}}\right )}{b d^2 \left (a^2+b^2\right )}-\frac {a^2 f \text {Li}_2\left (-e^{2 (c+d x)}\right )}{2 b d^2 \left (a^2+b^2\right )}+\frac {a^2 (e+f x) \log \left (\frac {b e^{c+d x}}{a-\sqrt {a^2+b^2}}+1\right )}{b d \left (a^2+b^2\right )}+\frac {a^2 (e+f x) \log \left (\frac {b e^{c+d x}}{\sqrt {a^2+b^2}+a}+1\right )}{b d \left (a^2+b^2\right )}-\frac {a^2 (e+f x) \log \left (e^{2 (c+d x)}+1\right )}{b d \left (a^2+b^2\right )}+\frac {2 a^3 (e+f x) \text {ArcTan}\left (e^{c+d x}\right )}{b^2 d \left (a^2+b^2\right )}-\frac {i a^3 f \text {Li}_2\left (-i e^{c+d x}\right )}{b^2 d^2 \left (a^2+b^2\right )}+\frac {i a^3 f \text {Li}_2\left (i e^{c+d x}\right )}{b^2 d^2 \left (a^2+b^2\right )}-\frac {2 a (e+f x) \text {ArcTan}\left (e^{c+d x}\right )}{b^2 d}+\frac {i a f \text {Li}_2\left (-i e^{c+d x}\right )}{b^2 d^2}-\frac {i a f \text {Li}_2\left (i e^{c+d x}\right )}{b^2 d^2}+\frac {f \text {Li}_2\left (-e^{2 (c+d x)}\right )}{2 b d^2}+\frac {(e+f x) \log \left (e^{2 (c+d x)}+1\right )}{b d}-\frac {(e+f x)^2}{2 b f} \end {gather*}
Antiderivative was successfully verified.
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Rule 2221
Rule 2317
Rule 2438
Rule 3799
Rule 4265
Rule 5680
Rule 5686
Rule 5692
Rule 5700
Rule 6874
Rubi steps
\begin {align*} \int \frac {(e+f x) \sinh (c+d x) \tanh (c+d x)}{a+b \sinh (c+d x)} \, dx &=\frac {\int (e+f x) \tanh (c+d x) \, dx}{b}-\frac {a \int \frac {(e+f x) \tanh (c+d x)}{a+b \sinh (c+d x)} \, dx}{b}\\ &=-\frac {(e+f x)^2}{2 b f}-\frac {a \int (e+f x) \text {sech}(c+d x) \, dx}{b^2}+\frac {a^2 \int \frac {(e+f x) \text {sech}(c+d x)}{a+b \sinh (c+d x)} \, dx}{b^2}+\frac {2 \int \frac {e^{2 (c+d x)} (e+f x)}{1+e^{2 (c+d x)}} \, dx}{b}\\ &=-\frac {(e+f x)^2}{2 b f}-\frac {2 a (e+f x) \tan ^{-1}\left (e^{c+d x}\right )}{b^2 d}+\frac {(e+f x) \log \left (1+e^{2 (c+d x)}\right )}{b d}+\frac {a^2 \int \frac {(e+f x) \cosh (c+d x)}{a+b \sinh (c+d x)} \, dx}{a^2+b^2}+\frac {a^2 \int (e+f x) \text {sech}(c+d x) (a-b \sinh (c+d x)) \, dx}{b^2 \left (a^2+b^2\right )}+\frac {(i a f) \int \log \left (1-i e^{c+d x}\right ) \, dx}{b^2 d}-\frac {(i a f) \int \log \left (1+i e^{c+d x}\right ) \, dx}{b^2 d}-\frac {f \int \log \left (1+e^{2 (c+d x)}\right ) \, dx}{b d}\\ &=-\frac {(e+f x)^2}{2 b f}-\frac {a^2 (e+f x)^2}{2 b \left (a^2+b^2\right ) f}-\frac {2 a (e+f x) \tan ^{-1}\left (e^{c+d x}\right )}{b^2 d}+\frac {(e+f x) \log \left (1+e^{2 (c+d x)}\right )}{b d}+\frac {a^2 \int \frac {e^{c+d x} (e+f x)}{a-\sqrt {a^2+b^2}+b e^{c+d x}} \, dx}{a^2+b^2}+\frac {a^2 \int \frac {e^{c+d x} (e+f x)}{a+\sqrt {a^2+b^2}+b e^{c+d x}} \, dx}{a^2+b^2}+\frac {a^2 \int (a (e+f x) \text {sech}(c+d x)-b (e+f x) \tanh (c+d x)) \, dx}{b^2 \left (a^2+b^2\right )}+\frac {(i a f) \text {Subst}\left (\int \frac {\log (1-i x)}{x} \, dx,x,e^{c+d x}\right )}{b^2 d^2}-\frac {(i a f) \text {Subst}\left (\int \frac {\log (1+i x)}{x} \, dx,x,e^{c+d x}\right )}{b^2 d^2}-\frac {f \text {Subst}\left (\int \frac {\log (1+x)}{x} \, dx,x,e^{2 (c+d x)}\right )}{2 b d^2}\\ &=-\frac {(e+f x)^2}{2 b f}-\frac {a^2 (e+f x)^2}{2 b \left (a^2+b^2\right ) f}-\frac {2 a (e+f x) \tan ^{-1}\left (e^{c+d x}\right )}{b^2 d}+\frac {a^2 (e+f x) \log \left (1+\frac {b e^{c+d x}}{a-\sqrt {a^2+b^2}}\right )}{b \left (a^2+b^2\right ) d}+\frac {a^2 (e+f x) \log \left (1+\frac {b e^{c+d x}}{a+\sqrt {a^2+b^2}}\right )}{b \left (a^2+b^2\right ) d}+\frac {(e+f x) \log \left (1+e^{2 (c+d x)}\right )}{b d}+\frac {i a f \text {Li}_2\left (-i e^{c+d x}\right )}{b^2 d^2}-\frac {i a f \text {Li}_2\left (i e^{c+d x}\right )}{b^2 d^2}+\frac {f \text {Li}_2\left (-e^{2 (c+d x)}\right )}{2 b d^2}+\frac {a^3 \int (e+f x) \text {sech}(c+d x) \, dx}{b^2 \left (a^2+b^2\right )}-\frac {a^2 \int (e+f x) \tanh (c+d x) \, dx}{b \left (a^2+b^2\right )}-\frac {\left (a^2 f\right ) \int \log \left (1+\frac {b e^{c+d x}}{a-\sqrt {a^2+b^2}}\right ) \, dx}{b \left (a^2+b^2\right ) d}-\frac {\left (a^2 f\right ) \int \log \left (1+\frac {b e^{c+d x}}{a+\sqrt {a^2+b^2}}\right ) \, dx}{b \left (a^2+b^2\right ) d}\\ &=-\frac {(e+f x)^2}{2 b f}-\frac {2 a (e+f x) \tan ^{-1}\left (e^{c+d x}\right )}{b^2 d}+\frac {2 a^3 (e+f x) \tan ^{-1}\left (e^{c+d x}\right )}{b^2 \left (a^2+b^2\right ) d}+\frac {a^2 (e+f x) \log \left (1+\frac {b e^{c+d x}}{a-\sqrt {a^2+b^2}}\right )}{b \left (a^2+b^2\right ) d}+\frac {a^2 (e+f x) \log \left (1+\frac {b e^{c+d x}}{a+\sqrt {a^2+b^2}}\right )}{b \left (a^2+b^2\right ) d}+\frac {(e+f x) \log \left (1+e^{2 (c+d x)}\right )}{b d}+\frac {i a f \text {Li}_2\left (-i e^{c+d x}\right )}{b^2 d^2}-\frac {i a f \text {Li}_2\left (i e^{c+d x}\right )}{b^2 d^2}+\frac {f \text {Li}_2\left (-e^{2 (c+d x)}\right )}{2 b d^2}-\frac {\left (2 a^2\right ) \int \frac {e^{2 (c+d x)} (e+f x)}{1+e^{2 (c+d x)}} \, dx}{b \left (a^2+b^2\right )}-\frac {\left (a^2 f\right ) \text {Subst}\left (\int \frac {\log \left (1+\frac {b x}{a-\sqrt {a^2+b^2}}\right )}{x} \, dx,x,e^{c+d x}\right )}{b \left (a^2+b^2\right ) d^2}-\frac {\left (a^2 f\right ) \text {Subst}\left (\int \frac {\log \left (1+\frac {b x}{a+\sqrt {a^2+b^2}}\right )}{x} \, dx,x,e^{c+d x}\right )}{b \left (a^2+b^2\right ) d^2}-\frac {\left (i a^3 f\right ) \int \log \left (1-i e^{c+d x}\right ) \, dx}{b^2 \left (a^2+b^2\right ) d}+\frac {\left (i a^3 f\right ) \int \log \left (1+i e^{c+d x}\right ) \, dx}{b^2 \left (a^2+b^2\right ) d}\\ &=-\frac {(e+f x)^2}{2 b f}-\frac {2 a (e+f x) \tan ^{-1}\left (e^{c+d x}\right )}{b^2 d}+\frac {2 a^3 (e+f x) \tan ^{-1}\left (e^{c+d x}\right )}{b^2 \left (a^2+b^2\right ) d}+\frac {a^2 (e+f x) \log \left (1+\frac {b e^{c+d x}}{a-\sqrt {a^2+b^2}}\right )}{b \left (a^2+b^2\right ) d}+\frac {a^2 (e+f x) \log \left (1+\frac {b e^{c+d x}}{a+\sqrt {a^2+b^2}}\right )}{b \left (a^2+b^2\right ) d}+\frac {(e+f x) \log \left (1+e^{2 (c+d x)}\right )}{b d}-\frac {a^2 (e+f x) \log \left (1+e^{2 (c+d x)}\right )}{b \left (a^2+b^2\right ) d}+\frac {i a f \text {Li}_2\left (-i e^{c+d x}\right )}{b^2 d^2}-\frac {i a f \text {Li}_2\left (i e^{c+d x}\right )}{b^2 d^2}+\frac {a^2 f \text {Li}_2\left (-\frac {b e^{c+d x}}{a-\sqrt {a^2+b^2}}\right )}{b \left (a^2+b^2\right ) d^2}+\frac {a^2 f \text {Li}_2\left (-\frac {b e^{c+d x}}{a+\sqrt {a^2+b^2}}\right )}{b \left (a^2+b^2\right ) d^2}+\frac {f \text {Li}_2\left (-e^{2 (c+d x)}\right )}{2 b d^2}-\frac {\left (i a^3 f\right ) \text {Subst}\left (\int \frac {\log (1-i x)}{x} \, dx,x,e^{c+d x}\right )}{b^2 \left (a^2+b^2\right ) d^2}+\frac {\left (i a^3 f\right ) \text {Subst}\left (\int \frac {\log (1+i x)}{x} \, dx,x,e^{c+d x}\right )}{b^2 \left (a^2+b^2\right ) d^2}+\frac {\left (a^2 f\right ) \int \log \left (1+e^{2 (c+d x)}\right ) \, dx}{b \left (a^2+b^2\right ) d}\\ &=-\frac {(e+f x)^2}{2 b f}-\frac {2 a (e+f x) \tan ^{-1}\left (e^{c+d x}\right )}{b^2 d}+\frac {2 a^3 (e+f x) \tan ^{-1}\left (e^{c+d x}\right )}{b^2 \left (a^2+b^2\right ) d}+\frac {a^2 (e+f x) \log \left (1+\frac {b e^{c+d x}}{a-\sqrt {a^2+b^2}}\right )}{b \left (a^2+b^2\right ) d}+\frac {a^2 (e+f x) \log \left (1+\frac {b e^{c+d x}}{a+\sqrt {a^2+b^2}}\right )}{b \left (a^2+b^2\right ) d}+\frac {(e+f x) \log \left (1+e^{2 (c+d x)}\right )}{b d}-\frac {a^2 (e+f x) \log \left (1+e^{2 (c+d x)}\right )}{b \left (a^2+b^2\right ) d}+\frac {i a f \text {Li}_2\left (-i e^{c+d x}\right )}{b^2 d^2}-\frac {i a^3 f \text {Li}_2\left (-i e^{c+d x}\right )}{b^2 \left (a^2+b^2\right ) d^2}-\frac {i a f \text {Li}_2\left (i e^{c+d x}\right )}{b^2 d^2}+\frac {i a^3 f \text {Li}_2\left (i e^{c+d x}\right )}{b^2 \left (a^2+b^2\right ) d^2}+\frac {a^2 f \text {Li}_2\left (-\frac {b e^{c+d x}}{a-\sqrt {a^2+b^2}}\right )}{b \left (a^2+b^2\right ) d^2}+\frac {a^2 f \text {Li}_2\left (-\frac {b e^{c+d x}}{a+\sqrt {a^2+b^2}}\right )}{b \left (a^2+b^2\right ) d^2}+\frac {f \text {Li}_2\left (-e^{2 (c+d x)}\right )}{2 b d^2}+\frac {\left (a^2 f\right ) \text {Subst}\left (\int \frac {\log (1+x)}{x} \, dx,x,e^{2 (c+d x)}\right )}{2 b \left (a^2+b^2\right ) d^2}\\ &=-\frac {(e+f x)^2}{2 b f}-\frac {2 a (e+f x) \tan ^{-1}\left (e^{c+d x}\right )}{b^2 d}+\frac {2 a^3 (e+f x) \tan ^{-1}\left (e^{c+d x}\right )}{b^2 \left (a^2+b^2\right ) d}+\frac {a^2 (e+f x) \log \left (1+\frac {b e^{c+d x}}{a-\sqrt {a^2+b^2}}\right )}{b \left (a^2+b^2\right ) d}+\frac {a^2 (e+f x) \log \left (1+\frac {b e^{c+d x}}{a+\sqrt {a^2+b^2}}\right )}{b \left (a^2+b^2\right ) d}+\frac {(e+f x) \log \left (1+e^{2 (c+d x)}\right )}{b d}-\frac {a^2 (e+f x) \log \left (1+e^{2 (c+d x)}\right )}{b \left (a^2+b^2\right ) d}+\frac {i a f \text {Li}_2\left (-i e^{c+d x}\right )}{b^2 d^2}-\frac {i a^3 f \text {Li}_2\left (-i e^{c+d x}\right )}{b^2 \left (a^2+b^2\right ) d^2}-\frac {i a f \text {Li}_2\left (i e^{c+d x}\right )}{b^2 d^2}+\frac {i a^3 f \text {Li}_2\left (i e^{c+d x}\right )}{b^2 \left (a^2+b^2\right ) d^2}+\frac {a^2 f \text {Li}_2\left (-\frac {b e^{c+d x}}{a-\sqrt {a^2+b^2}}\right )}{b \left (a^2+b^2\right ) d^2}+\frac {a^2 f \text {Li}_2\left (-\frac {b e^{c+d x}}{a+\sqrt {a^2+b^2}}\right )}{b \left (a^2+b^2\right ) d^2}+\frac {f \text {Li}_2\left (-e^{2 (c+d x)}\right )}{2 b d^2}-\frac {a^2 f \text {Li}_2\left (-e^{2 (c+d x)}\right )}{2 b \left (a^2+b^2\right ) d^2}\\ \end {align*}
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Mathematica [A]
time = 1.94, size = 441, normalized size = 0.85 \begin {gather*} \frac {-b d e (c+d x)+b c f (c+d x)+\frac {1}{2} b f (c+d x)^2-2 a d e \text {ArcTan}(\cosh (c+d x)+\sinh (c+d x))+2 a c f \text {ArcTan}(\cosh (c+d x)+\sinh (c+d x))-2 a f (c+d x) \text {ArcTan}(\cosh (c+d x)+\sinh (c+d x))+b f (c+d x) \log (2 \cosh (c+d x) (\cosh (c+d x)-\sinh (c+d x)))+b d e \log (1+\cosh (2 (c+d x))+\sinh (2 (c+d x)))-b c f \log (1+\cosh (2 (c+d x))+\sinh (2 (c+d x)))+\frac {a^2 \left (-\frac {1}{2} f (c+d x)^2+f (c+d x) \log \left (1+\frac {b e^{c+d x}}{a-\sqrt {a^2+b^2}}\right )+f (c+d x) \log \left (1+\frac {b e^{c+d x}}{a+\sqrt {a^2+b^2}}\right )+d e \log (a+b \sinh (c+d x))-c f \log (a+b \sinh (c+d x))+f \text {PolyLog}\left (2,\frac {b e^{c+d x}}{-a+\sqrt {a^2+b^2}}\right )+f \text {PolyLog}\left (2,-\frac {b e^{c+d x}}{a+\sqrt {a^2+b^2}}\right )\right )}{b}+i a f \text {PolyLog}(2,-i (\cosh (c+d x)+\sinh (c+d x)))-i a f \text {PolyLog}(2,i (\cosh (c+d x)+\sinh (c+d x)))-\frac {1}{2} b f \text {PolyLog}(2,-\cosh (2 (c+d x))+\sinh (2 (c+d x)))}{\left (a^2+b^2\right ) d^2} \end {gather*}
Antiderivative was successfully verified.
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Maple [B] Both result and optimal contain complex but leaf count of result is larger than twice
the leaf count of optimal. 3881 vs. \(2 (484 ) = 968\).
time = 5.74, size = 3882, normalized size = 7.52
method | result | size |
risch | \(\text {Expression too large to display}\) | \(3882\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.40, size = 750, normalized size = 1.45 \begin {gather*} -\frac {{\left (a^{2} + b^{2}\right )} d^{2} f x^{2} + 2 \, {\left (a^{2} + b^{2}\right )} d^{2} x \cosh \left (1\right ) + 2 \, {\left (a^{2} + b^{2}\right )} d^{2} x \sinh \left (1\right ) - 2 \, a^{2} f {\rm Li}_2\left (\frac {a \cosh \left (d x + c\right ) + a \sinh \left (d x + c\right ) + {\left (b \cosh \left (d x + c\right ) + b \sinh \left (d x + c\right )\right )} \sqrt {\frac {a^{2} + b^{2}}{b^{2}}} - b}{b} + 1\right ) - 2 \, a^{2} f {\rm Li}_2\left (\frac {a \cosh \left (d x + c\right ) + a \sinh \left (d x + c\right ) - {\left (b \cosh \left (d x + c\right ) + b \sinh \left (d x + c\right )\right )} \sqrt {\frac {a^{2} + b^{2}}{b^{2}}} - b}{b} + 1\right ) + 2 \, {\left (i \, a b f - b^{2} f\right )} {\rm Li}_2\left (i \, \cosh \left (d x + c\right ) + i \, \sinh \left (d x + c\right )\right ) + 2 \, {\left (-i \, a b f - b^{2} f\right )} {\rm Li}_2\left (-i \, \cosh \left (d x + c\right ) - i \, \sinh \left (d x + c\right )\right ) + 2 \, {\left (a^{2} c f - a^{2} d \cosh \left (1\right ) - a^{2} d \sinh \left (1\right )\right )} \log \left (2 \, b \cosh \left (d x + c\right ) + 2 \, b \sinh \left (d x + c\right ) + 2 \, b \sqrt {\frac {a^{2} + b^{2}}{b^{2}}} + 2 \, a\right ) + 2 \, {\left (a^{2} c f - a^{2} d \cosh \left (1\right ) - a^{2} d \sinh \left (1\right )\right )} \log \left (2 \, b \cosh \left (d x + c\right ) + 2 \, b \sinh \left (d x + c\right ) - 2 \, b \sqrt {\frac {a^{2} + b^{2}}{b^{2}}} + 2 \, a\right ) - 2 \, {\left (a^{2} d f x + a^{2} c f\right )} \log \left (-\frac {a \cosh \left (d x + c\right ) + a \sinh \left (d x + c\right ) + {\left (b \cosh \left (d x + c\right ) + b \sinh \left (d x + c\right )\right )} \sqrt {\frac {a^{2} + b^{2}}{b^{2}}} - b}{b}\right ) - 2 \, {\left (a^{2} d f x + a^{2} c f\right )} \log \left (-\frac {a \cosh \left (d x + c\right ) + a \sinh \left (d x + c\right ) - {\left (b \cosh \left (d x + c\right ) + b \sinh \left (d x + c\right )\right )} \sqrt {\frac {a^{2} + b^{2}}{b^{2}}} - b}{b}\right ) + 2 \, {\left (-i \, a b c f + b^{2} c f + i \, a b d \cosh \left (1\right ) - b^{2} d \cosh \left (1\right ) + i \, a b d \sinh \left (1\right ) - b^{2} d \sinh \left (1\right )\right )} \log \left (\cosh \left (d x + c\right ) + \sinh \left (d x + c\right ) + i\right ) + 2 \, {\left (i \, a b c f + b^{2} c f - i \, a b d \cosh \left (1\right ) - b^{2} d \cosh \left (1\right ) - i \, a b d \sinh \left (1\right ) - b^{2} d \sinh \left (1\right )\right )} \log \left (\cosh \left (d x + c\right ) + \sinh \left (d x + c\right ) - i\right ) + 2 \, {\left (-i \, a b d f x - b^{2} d f x - i \, a b c f - b^{2} c f\right )} \log \left (i \, \cosh \left (d x + c\right ) + i \, \sinh \left (d x + c\right ) + 1\right ) + 2 \, {\left (i \, a b d f x - b^{2} d f x + i \, a b c f - b^{2} c f\right )} \log \left (-i \, \cosh \left (d x + c\right ) - i \, \sinh \left (d x + c\right ) + 1\right )}{2 \, {\left (a^{2} b + b^{3}\right )} d^{2}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\left (e + f x\right ) \sinh {\left (c + d x \right )} \tanh {\left (c + d x \right )}}{a + b \sinh {\left (c + d x \right )}}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int \frac {\mathrm {sinh}\left (c+d\,x\right )\,\mathrm {tanh}\left (c+d\,x\right )\,\left (e+f\,x\right )}{a+b\,\mathrm {sinh}\left (c+d\,x\right )} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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